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CS610
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Which Of The Following Is The Valid Host Range For The Ip Address 192.168.168.188 255.255.255.192?
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192.168.168.129-190
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192.168.168.129-191
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192.168.168.128-190
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192.168.168.128-192
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A
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CS610
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Which Of The Following Are Interior Routing Protocols?
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Rip
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Ospf
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Bgp
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Rip And Ospf
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D
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CS610
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A One-To-Many Communication Between A Source And A Specific Group Of Hosts Is Classified As A Communication
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Unicast
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Multicast
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Broadcast
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Unicast & Multicast
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B
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CS610
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Igps Stand For ___________
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Internal Gateway Protocols
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Interior Gateway Protocols
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Intermediate Gateway Protocols
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None Of The Given
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B
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CS610
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Network Cable Lies On Layer
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Application
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Network
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Physical
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None Od These
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C
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CS610
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Ospf Includes __________ Address Mask With Each Address
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30Bit
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32Bit
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34Bit
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None Of The Given
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B
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CS610
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The Gigabit Ethernet Hardware Operates At A Rate Of --------
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10 Mbps
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100 Mbps
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1000 Mbps
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None Of The Given
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C
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CS610
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Which Protocol Is Used To Send A Destination Network Unknown Message Back To Originating Hosts?
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Tcp
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Arp
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Icmp
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Bootp
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C
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CS610
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Ipv6 __________ Is Responsible For Fragmentation. Routers Simply Drop Datagram’S Larger Than Network
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Destination
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Intermediate Routers
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Source
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Medium
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C
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CS610
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Most Nics Contain __________ Circuitry That Allows The Nic To Operate Independent Of The Cpu
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Dma(Direct Memory Access)
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Multiplexer
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Transceiver
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None Of The Given
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A
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CS610
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In Which Method Of Address Resolution Protocol The Implimentation Is More Difficult? Were T Stands For Table Lookup C For Closed-Form Computation And D For Data Exchange?
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T C
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T
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C
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D
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D
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CS610
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Preliminary Version Of Ip Was Called ___________
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Ip - New Generation (Ipng)
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Ip - Next Generation (Ipng)
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Ip - Net Generation (Ipng)
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None Of The Given
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B
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CS610
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---------- Scheme Which Is Designed To Help Detect Transmissions Errors Send One Extra Bit Of Information With Each Character
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Parity
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Parity
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Crc
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None Of Given
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A
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CS610
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The Maximum Size Of An Ethernet Segment Is__________
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250 Meters
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500 Meters
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700 Meters
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None Of The Given
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B
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CS610
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In Direct Point To Point Communication Adding The Nth Computer Requires------------ New Connections
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(N^2 –N)/2
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N^2
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N-1
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None Of The Given
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A
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CS610
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The Number Of Connections Needed For N Computer In Direct Point To Point Communication Is Equal To
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(N^2 –N)/2
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N^2
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N(N-1)
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None Of The Given
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A
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CS610
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These Packets Serve Same Purpose On __________ As Frames On
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Intranet Lan
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Internet Wan
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Intranet Wan
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Internet Lan
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D
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CS610
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An Interface For Twisted Pair Ethernet Must Have A __________ Connector And Must Generate Signals According To The__________ Specification
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Bnc- T Base 10
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Rj 45- T Base 10
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Bnc-T Base 5
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Rj 45-T Base 2
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B
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CS610
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Ipv6 128 Bits Address Includes Network Prefix And __________
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Host Sufix
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Host Prefix
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Source Prefix
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None Of The Given
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A
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CS610
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For __________ Information About Forwarding Is Stored In A Routing Table Which Is Initialized At System Initialization And Must Be Updated As Network Topology Changes
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Efficiency
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Security
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Accuracy
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Anomalies
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A
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