Code Question Option A Option B Option C Option D Answer
CS302 A Synchronous Decade Counter Will Have Flip-Flops 3 4 7 10 A
CS302 A Transparent Mode Means __________ The Changes In The Data At The Inputs Of The Latch Are Seen At The Output The Changes In The Data At The Inputs Of The Latch Are Not Seen At The Output Propagation Delay Is Zero (Output Is Immediately Changed When Clock Signal Is Applied) Input Hold Time Is Zero (No Need To Maintain Input After Clock Transition) A
CS302 Addition Of Two Octal Numbers “36” And “71” Results In __________ 213 123 127 345 C
CS302 An Alternate Method Of Implementing Comparators Which Allows The Comparators To Be Easily Cascaded Without The Need For Extra Logic Gates Is Using A Single Comparator Using Iterative Circuit Based Comparators Connecting Comparators In Vertical Hierarchy Extra Logic Gates Are Always Required B
CS302 An Astable Multivibrator Is Known As A(N) Oscillator Booster One-Shot Dual-Shot C
CS302 An Example Of Sop Expression Is A + B(C + D) A B + Ac + Ab C (A + B + C)(A + B + C) Both (A) Nad (B D
CS302 Assume That A 4-Bit Serial In/Serial Out Shift Register Is Initially Clear. We Wish To Store The Nibble 1100. What Will Be The 4-Bit Pattern After The Second Clock Pulse? (Right-Most Bit First.) 1100 0011 0000 1111 C
CS302 Asynchronous Mean That__________ Each Flip-Flop After The First One Is Enabled By The Output Of The Preceding Flip-Flop Each Flip-Flop Is Enabled By The Output Of The Preceding Flip-Flop Each Flip-Flop Except The Last One Is Enabled By The Output Of The Preceding Flip-Flop Each Alternative Flip-Flop After The First One Is Enabled By The Output Of The Preceding Flip-Flop D
CS302 At T0 The Value Stored In A 4-Bit Left Shift Was “1”. What Will Be The Value Of Register After Three Clock Pulses? 2 4 6 8 D
CS302 Bi-Stable Devices Remain In Either Of Their ___________ States Unless The Inputs Force The Device To Switch Its State Ten Eight Three Two D
CS302 Bi-Stable Devices Remain In Either Of Their States Unless The Inputs Force The Device To Switch Its State 10 8 3 2 D
CS302 Caveman Number System Is Base Number System 2 5 10 16 B
CS302 Consider A=1 B=0 C=1. A B And C Represent The Input Of Three Bit Nand Gate The Output Of The Nand Gate Will Be Zero One Undefined No Output As Input Is Invalid B
CS302 Demultiplexer Converts Data To __________ Data Parallel Data Serial Data Serial Data Parallel Data Encoded Data Decoded Data All Of The Given Options B
CS302 Demultiplexer Is Also Called Data Selector Data Router Data Distributor Data Encoder C
CS302 Determine The Values Of A B C And D That Make The Sum Term A(Bar) + B+C(Bar)+D Equal To Zero A = 1 B = 0 C = 0 D = 0 A = 1 B = 0 C = 1 D = 0 A = 0 B = 1 C = 0 D = 0 A = 1 B = 0 C = 1 D = 1 B
CS302 Divide-By-160 Counter Is Acheived By Using Flip-Flop And Div 10 Flip-Flop And Div 16 Div 16 And Div 32 Div 16 And Div 10 C
CS302 Don’T Care Conditions Are Marked As __________ In The Output Column Of The Function Table 0 1 X None Of The Given Options C
CS302 Dram Stands For __________ Dynamic Ram Data Ram Demoduler Ram None Of Given Options A
CS302 Excess-8 Code Assigns To “+7” 0000 1001 1000 1111 A