CS101
532
CS201
225
CS301
232
CS302
174
CS304
192
CS401
224
CS402
258
CS403
228
CS408
113
CS411
121
CS502
249
CS504
268
CS601
679
CS604
381
CS605
261
CS607
184
CS609
230
CS610
300
CS614
100
CS703
65
Code | Question | Option A | Option B | Option C | Option D | Answer | |
---|---|---|---|---|---|---|---|
CS401 | Each Screen Location Corresponds To A Word The Lower Byte Of This Word Contains ___________ | The Character Code | The Attribute Byte | The Parameters | The Dimensions | A | |
CS401 | Each Thread Can Have Their Own | Execution Area | Stack | Memory | Array | B | |
CS401 | Every Bit Of Line Status In Serial Port Conveys __________ Information. | Different | Same | Partial | Full | A | |
CS401 | Execution Of The Instruction “Mov Word [Es : 0] 0X0741” Will Print | “A” Appear On The Top Left Of Screen | “A” Appear On The Top Right Of Screen | “A” Appear On The Center Of Screen | “A” Appear On The Bottom Left Of Screen | A | |
CS401 | Execution Of The Instruction “Mov Word [Es : 0] 0X0741” Will Print Character “A” On Screen Color Of The Character Will Be | Black | White | Red | Blue | B | |
CS401 | For Memory We Define Two Dimensions. The First Dimension Defines How Many __________Bits Are There In A Single Memory Cell | Parallel | Vertical | Long | Short | A | |
CS401 | For The Execution Of The Instruction “Div Bl” The Implied Dividend Will Be Stored In | Ax | Bx | Cx | Dx | A | |
CS401 | Foreground And Background Parameter Will Be | 32Bits | 16Bits | 8Bits | 4Bits | C | |
CS401 | Fs And Fs And Gs Are Two __________ In Protected Mode. | Segment Registers | Segment Selectors | Stack Pointers | Register Pointers | B | |
CS401 | How Many Prevalent Calling Conventions Do Exist | 1 | 2 | 3 | 4 | B | |
CS401 | Idt Stands For __________ | Interrupt Descriptor Table | Individual Descriptor Table | Inline Data Table | Interrupt Descriptor Table | A | |
CS401 | If “Bb” Is The Opcode Of The Instruction Which States To “Move A Constant Value To Ax Register” The Hexadecimal Representation (Using Little Endian Notation) Of The Instruction “Mov Ax 336” (“150” In Hexadecimal Number System) Will Be: | 0Xbb0150 | 0X5001Bb | 0X01Bb50 | 0Xbb5001 | D | |
CS401 | If Contains Decimal -2 And Bx Contains Decimal 2 Then After The Execution Of Instructions: Cmp Ax Bx Ja Label | Jump Will Be Taken | Zero Flag Will Set | Zf Will Contain Value -4 | Jump Will Not Be Taken | A | |
CS401 | If D Is “35” Is Shift To Left 2 Bits The New Value | 17 | 35 | 70 | 140 | D | |
CS401 | If The Address Of Memory Location Num1 Is 0117 And Its Content Is 0005 Then After Execution Of The Instruction “ Mov Bx Num1” Bx Will Contain | 0005 | 0117 | Num1 | 1701 | B | |
CS401 | If The Decimal Number “35” Is Shifted By Two Bit To Left The New Value Will Be | 35 | 70 | 140 | 17 | C | |
CS401 | If The Direction Of The Processing Of A String Is From Higher Addresses Towards Lower Addresses Then | Zf Is Cleared | Df Is Cleared | Zf Is Set | Df Is Set | D | |
CS401 | If We Want To Divide A Signed Number By 2 This Operation Can Better Be Accomplished By | Shr | Sar | Shl | Sal | B | |
CS401 | In 68K Processors There Is A __________ Program Counter (Pc) That Holds The Address Of Currently Executing Instruction | 8Bit | 16Bit | 32Bit | 64Bit | C | |
CS401 | In 68K Processors There Is A 32Bit __________ That Holds The Address Of Currently Executing Instruction | Program Counter | Stack Pointer | Register | Stack | A |