Code Question Option A Option B Option C Option D Answer
CS402 Bottem Up Parsing Can Be Determined Similar To That Of Top Down Parsing With The Change That In This Case The Process Is Started With The Given String And The Tree Is Extended Till “S “Is Regular Non Regular Obtain Finite C
CS402 Can A Turing Machines Head Ever Be In The Same Location In Two Successive Steps? True False True But Only In Finite Languages True But Only In Infinite Langauges B
CS402 Cfg Is Said To Be A Regular Grammar If It Generates The Regular Language I.E.A Cfg Is Said To Be A Regular Grammar In Which Each Production Is One Of The: Three Forms One Form Four Forms Two Forms D
CS402 Cfg Stands For ___________ Context Free Graph Context Free Grammar Context Finite Graph Context Finite Grammar B
CS402 Choose The Correct Statement A Mealy Machine Generates No Language As Such A Moore Machine Generates No Language As Such A Mealy Machine Has No Terminal State All Of These C
CS402 Choose The Correct Statement A Mealy Machine Generates No Language As Such A Moore Machine Generates No Language As Such A Mealy Machine Has No Terminal State All Of These C
CS402 Choose The Incorrect (False) Statement A Mealy Machine Generates No Language As Such A Mealy Machine Has No Terminal State For A Given Input String Length Of The Output String Generated By A Moore Machine Is Not More Than The Length Of The Output String Generated By That Of A Mealy Machine All Of These C
CS402 Choose The Incorrect Statement (A+B)*Aa(A+B)* Generates Regular Language A Language Consisting Of All Strings Over ?={A B} Having Equal Number Of A’S And B’S Is A Regular Language Every Language That Can Be Expressed By Fa Can Also Be Expressed By Re None Of These D
CS402 Closure Of An Fa Is Same As __________ Of An Fa With Itself Except That The Initial State Of The Required Fa Is A Final State As Well Union Sum Concatenation Intersection C
CS402 Consider A Language L Defined Over An Alphabet ? If Two Strings X And Y Defined Over ? Are Run Over An Fa Accepting The Language L Then X And Y Are Said To Belong To The Same ___________ If They End In The Same ___________ Class State Final Infinite Regular Nonregular All Of Above A
CS402 Consider The Following Cfg: (Note: ^ Means Null) S->A|Xb|Aya X->Y|^ Y->B|X Which Nonterminal(S) Is/Are Not Nullable S X Y S X And Y B
CS402 Consider The Following Cfg: S?As|Bs|Aas|? Can Be Observed That The Word Aaa Can Be Derived From More Than One Production Tree Two Producton Tree Total Language Tree All Of Above A
CS402 Consider The Following Gfc : S?Aa|Bb A?Aa|B B?As|? Here S?Aaand A?B Are Null Productions While B?? Is Null Able Production True False Na Na B
CS402 Consider The Language L Of Strings Defined Over S = {A B} Ending In A There Are Finite Many Classes Generated By L So L Is Regular There Are Infinite Many Classes Generated By L So L Is Regular There Are Finite Many Classes Generated By L So L Is Non-Regular There Are Infinite Many Classes Generated By L So L Is Non-Regular B
CS402 Considering Fa1 And Fa2 Having 2 States Each. Now Fa1+Fa2 Can Have Maximum __________ Number Of States 2 3 More Than 3 None Of Them D
CS402 Converting Each Of The Final States Of F To Non-Final States And Old Non-Final States Of F To Final States Fa Thus Obtained Will Reject Every String Belonging To L And Will Accept Every String Defined Over S Not Belonging To L. Is Called Complement Of L Finite Automata Of L Transition Graph Of L Regular Expression Of L A
CS402 Converting The Given Cfg In Cnf Is The First Rule Of Cyk Algorithm Cky Algorithm Kyc Algorithm Cnk Algorithm A
CS402 Does The Empty String Match The Regular Expression |Y+A|? True False Some Times True & Sometimes False None Of Given B
CS402 Enters In A Specific State But There Is No Way To Leave It Then That Specific State Is Called Dead State Waste Basket Davey John Locker All Of These D
CS402 Every Fa Should Be __________ Deterministic Non- Deterministic Deterministic & Non- Deterministic None Of These A