CS401
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Programmable Interrupt Controller Has Two Ports 20 And 21. Port 20 Is The Control Port While Port 21 Is __________
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The Interrupt Mask Register
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Interrupt Port
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Output Port
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Input Port
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A
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CS401
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Types Of Jump Are:
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Short Near
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Short Near Far
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Near Far
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Short Far
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B
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CS401
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Cmps Instruction Subtracts The Source Location To The Destination Location. Destination Location Always Lies In
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Ds:Si
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Ds:Di
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Es:Si
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Es:Di
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D
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CS401
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After The Execution Of Instruction “Ret 2”
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Sp Is Incremented By 2
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Sp Is Decremented By 2
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Sp Is Incremented By 4
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Sp Is Decremented By 4
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C
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CS401
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Which Bit Sets The Character Blinking On The Screen?
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5
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6
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7
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8
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C
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CS401
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The Physical Address Of The Stack Is Obtained By
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Ss:Si Combination
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Ss:Sp Combination
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Es:Bp Combination
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Es:Sp Combination
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B
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CS401
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When Two Devices In The System Want To Use The Same Irq Line Then What Will Happen?
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An Irq Collision
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An Irq Conflict
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An Irq Crash
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An Irq Blockage
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B
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CS401
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The Screen Is Two Dimensional Space Having:
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25 Rows And 25 Columns
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25 Rows And 80 Columns
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80 Rows And 80 Columns
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80 Rows And 25 Columns
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D
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CS401
|
If “Bb” Is The Opcode Of The Instruction Which States To “Move A Constant Value To Ax Register” The Hexadecimal Representation (Using Little Endian Notation) Of The Instruction “Mov Ax 336” (“150” In Hexadecimal Number System) Will Be:
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0Xbb0150
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0X5001Bb
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0X01Bb50
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0Xbb5001
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D
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CS401
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The Basic Function Of Scas Instruction Is To
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Compare
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Scan
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Sort
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Move Data
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A
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CS401
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In Device Attribute Word Which Of The Following Bit Decides Whether It Is A Character Device Or A Block Device
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Bit 12
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Bit 13
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Bit 14
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Bit 15
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D
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CS401
|
When A Very Large Number Is Divided By Very Small Number So That The Quotient Is Larger Than The Space Provided This Is Called
|
Divide Logical Error
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Divide Overflow Error
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Divide Syntax Error
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An Illegal Instruction
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B
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CS401
|
Which Bit Of The Attributes Byte Represents The Red Component Of Background Color ?
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3
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4
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5
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6
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D
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CS401
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The Execution Of The Instruction “Mov Word [Es : 0] 0X0741” Will Print Character “A” On Screen Background Color Of The Screen Will Be
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Black
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White
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Red
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Blue
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A
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CS401
|
8088 Is A __________
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16 Bit Processor
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32 Bit Processor
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64 Bit Processor
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128 Bit Processor
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A
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CS401
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For Memory We Define Two Dimensions. The First Dimension Defines How Many __________Bits Are There In A Single Memory Cell
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Parallel
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Vertical
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Long
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Short
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A
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CS401
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In A Video Memory Each Screen Location Corresponds To
|
One Byte
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Two Bytes
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Four Bytes
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Eight Bytes
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B
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CS401
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The Thread Registration Code Initializes The Pcb And Adds It To The Linked List So That The __________ Will Give It A Turn.
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Assembler
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Scheduler
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Linker
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Debugger
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B
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CS401
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Decrements Sp (The Stack Pointer) By Two And Then Transfers A Word From The Source Operand To The Top Of Stack
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Push
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Pop
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Call
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Ret
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A
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CS401
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8088 Is A 16Bit Processor With Its Accumulator And All Registers Of __________.
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6 Bits
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16 Bits
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32 Bits
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64 Bits
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B
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